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Posted
I've been using the formula:
Soap ppm (KOH) = ml HCl x Normality x 320,400/g sample.

Here's an example using .01N HCl titrant.
1.5ml HCl needed to reach end point (Bromo Blue).
1.5 x .01N x 320,400/10g (sample size)= 480.6ppm

Checking the math though I get a vastly different answer.
A .01N HCl solution contains .365mols HCl.
.365/1000= .000365mol HCl per ml.
I needed 1.5ml in the example so 1.5 x.000365= .0005475mols HCl used to reach the end point.
This tells me that there are .0005475mols K soap in the 10g sample.
I'm using a molecular weight of 320.4g per mole for Potassium oleate soap.
.000547x320.4= .175419g Potassium Oleate in the 10g sample.

The formula for ppm is:
ppm = weight(g) of solute/ weight(g) of solution x 1,000,000.
weight of the solute (K soap) = .175419g
weight of the solution = 10g
.175419/10=.0175419x1,000,000 = 17,541.9ppm

Help someone, where is my math wrong?
 
Location: central virginia | Registered: 13 March 2008Reply With QuoteEdit or Delete MessageReport This Post
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I copied this question to the U.K. forum as well.
Mespilus and Countrypaul pointed out my error.
My error was right in the beginning saying that a .01N solution contained .365mols as opposed to .01 moles and weighs .365g.
So the formula as written at the top is spot on.
My error.

Thanks for the help guys.
 
Location: central virginia | Registered: 13 March 2008Reply With QuoteEdit or Delete MessageReport This Post
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