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Is there a mathematical formula for the amount of Lye or KOH to add to certain amount of vegetable oil? I am looking for something I can plug into an excel spreadsheet. In other words, W gallons of oil times X titration / Y KOH purity level = Z grams of KOH.

I can't seem to find a formula on line. All I can find is a recipe calculator where you have to input the fields to get the outcome, but not the underlying formula.

I appreciate the help. Thanks!
 
Registered: 24 July 2006Reply With QuoteEdit or Delete MessageReport This Post
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Never mind - I figured it out. Liters x 7 grams + 1 gram for each titration. Also, you should divide the total grams by your KOH purity level. So, 100 liters of oil that titrates at 3 would be the following, (assuming a 90% purity of KOH):

100 x ((7+3)/.9) = 1,111 grams of KOH

Correct me if I'm wrong, but I think that's it.
 
Registered: 24 July 2006Reply With QuoteEdit or Delete MessageReport This Post
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close but don't purity adjust the titrataion..its self adjusting.

-dkenny


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Location: RTP, North Carolina | Registered: 15 December 2004Reply With QuoteEdit or Delete MessageReport This Post
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EXCELLENT point! So, the 90% purity is already factored into my titration of 3, but it's NOT included in my base titration of 7. So, same scenario, my formula would be as follows:

100 liters of oil x ((7/.9)+3) = 1,078 grams.

That, I believe is the correct formula. Feel free to disagree.
 
Registered: 24 July 2006Reply With QuoteEdit or Delete MessageReport This Post
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Right on Guage.
 
Location: central virginia | Registered: 13 March 2008Reply With QuoteEdit or Delete MessageReport This Post
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